BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

rate problem

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
Senior | Next Rank: 100 Posts
Posts: 40
Joined: Fri Nov 27, 2009 7:48 pm
Thanked: 1 times

rate problem

by rtaha2412 » Mon Jan 03, 2011 3:21 pm
If Bill drove 1.5 times slower than normal and was late for school today, how long does it normally take Bill to drive to school? (Assume that each day Bill takes the same route).

1. It took Bill 15 minutes longer to drive to school today than normal.
2. The distance between home and school is 15 miles.
Top
Source: — Data Sufficiency |
User avatar
Legendary Member
Posts: 543
Joined: Tue Jun 15, 2010 7:01 pm
Thanked: 147 times
Followed by:3 members

by anshumishra » Mon Jan 03, 2011 3:43 pm
rtaha2412 wrote:If Bill drove 1.5 times slower than normal and was late for school today, how long does it normally take Bill to drive to school? (Assume that each day Bill takes the same route).

1. It took Bill 15 minutes longer to drive to school today than normal.
2. The distance between home and school is 15 miles.
v -> Bill's speed
t -> time taken by Bill to reach school
d -> distance b/w school
t = d/v = ?

Statement 1 :

d/v = 15 + 3d/2v -> Sufficient

Statement 2 :
d = 15 miles

Not sufficient, as no info of v.

Hence A
Thanks
Anshu

(Every mistake is a lesson learned )
Top
User avatar
GMAT Instructor
Posts: 15539
Joined: Tue May 25, 2010 12:04 pm
Location: New York, NY
Thanked: 13060 times
Followed by:1906 members
GMAT Score:790

by GMATGuruNY » Mon Jan 03, 2011 4:30 pm
rtaha2412 wrote:If Bill drove 1.5 times slower than normal and was late for school today, how long does it normally take Bill to drive to school? (Assume that each day Bill takes the same route).

1. It took Bill 15 minutes longer to drive to school today than normal.
2. The distance between home and school is 15 miles.
The wording of this question is strange: what does it mean to drive "1.5 times slower"? If the rate is 4 miles per hour, (1.5)*4 = 6, which is a faster rate, not a slower rate. I'm going to assume that the question is trying to convey the following: that the time was 1.5 times longer. In other words, that it took Bill 1.5 times as long to get to school today as it normally would.

Let x = normal time to drive to school.
Time to drive to school today = 1.5x.

Statement 1:
1.5x = x+15
.5x=15
x=30.
Sufficient.

Statement 2:
The distance does not help us to determine the normal time.
Insufficient.

The correct answer is A.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Top
Post new topic Post Reply
• Page 1 of 1