- Neilsheth2
- Senior | Next Rank: 100 Posts
- Posts: 65
- Joined: Sun Jun 03, 2012 8:58 am
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how could it be C since if we plug in numbers lets say:-
a=-5 , b=5..Satisfying a<b
x=2 ,y=3 satisfying x<y...We get a YES answer for a^x<b^y
While when we plug
a=-7 , b=-5..Satisfying a<b
x=2 ,y=3 satisfying x<y...We get a NO answer for a^x<b^y
Need some help.
Thanks in advance!
a=-5 , b=5..Satisfying a<b
x=2 ,y=3 satisfying x<y...We get a YES answer for a^x<b^y
While when we plug
a=-7 , b=-5..Satisfying a<b
x=2 ,y=3 satisfying x<y...We get a NO answer for a^x<b^y
Need some help.
Thanks in advance!
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