nikhilgmat31 wrote:The students of two classes appeared for an exam. The average score for both classes combined was 70. The students of the first class registered an average score of 80. If the total number of students was 50 and the number of students in the first class was greater than the number of students in the second class, which of the following could be the average score for the second class?
1.30
2.60
3.75
A. I only
B. II only
C. III only
D. I, II and III
E. Neither I nor II and III
Use ALLIGATION to evaluate the three statements.
Let F = the number of students in the first class and S = the number of students in the second class.
Statement I: 30
Step 1: Plot the 3 averages on a number line, with the averages for F and S on the ends and the average for the mixture of classes in the middle.
F 80-----------------70----------------30 S
Step 2: Calculate the distances between the averages.
F 80--------
10-------70--------
40------30 S
Step 3: Determine the ratio in the mixture.
The ratio of F to S is equal to the RECIPROCAL of the distances in red.
F:S = 40:10.
Here, F=40 and S=10, for a total of 50 students.
Since Statement I is possible, eliminate B, C and E.
Statement II: 60
Step 1: Plot the 3 averages on a number line, with the averages for F and S on the ends and the average for the mixture of classes in the middle.
F 80-----------------70----------------60 S
Here, the average for the mixture (70) is HALFWAY between the averages for F and S, implying that the two classes have the SAME NUMBER OF STUDENTS.
Since the first class must have more students than the second, Statement II is not possible.
Eliminate D.
The correct answer is
A.
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