If z is an integer and 4^z < 213, what is z?
z= integer
4^z < 213
4*4=16*4=64*4=256 HENCE z < 4
(1) 4^(z + 1) - 4^(z - 1) > 213
4^z(4^+1 - 4^-1) > 213
4^z(4 - 1/4) > 213
4^z(15/4) > 213
4^z > 213 * 4/15
4^z > 3*71*4*(1/15)
4^z > 284/15
4^z > 56.80
Because z is an integer, then z must be 3!!!
(2) 4^(z + 1) + 4^z > 213
4^z(4+1) > 213
4^z(5) > 213
4^z > 213/5
4^z > 42.6
Because z is an integer, then z must be 3!!!
Correct Answer [spoiler](D)[/spoiler]
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