DS problem on Factors and Even/Odd Need Explanation

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by jkaustubh » Thu Nov 15, 2012 8:39 pm
The answer should be D according to me.

See

X is a factor of Y
Y is a factor of Z

Now Statement 1:

xz is even

from the question it is clear that x is a factor of z.

So if X is even, then Z has to be even, hence XZ will be even.

Now if XZ is even and X is not even then Z has to be even

Hence Statement 1 is sufficient.

Statement 2:

Y is a factor of Z.

Hence if Y will be even then Z will surely be even.

Hence Statement 2 is sufficient.

Hence the answer shall be D

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by soni_pallavi » Fri Nov 16, 2012 2:48 am
This is the answer :)

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by Brent@GMATPrepNow » Fri Nov 16, 2012 7:37 am
soni_pallavi wrote:The positive integers x,y and z are such that x is a factor of y and y is a factor of z.Is z even?

1) xz is even
2) y is even
Target question: Is z even?

Given: x is a factor of y, and y is a factor of z.

There's a nice rule that says, "If D is a factor (divisor) of N, then N = kD for some integer k"
So, if x is a factor of y, then y = kx for some integer k.
Also, if y is a factor of z, then z = jy for some integer j

Statement 1: xz is even
This sets up two possible cases (x is even or z is even). We'll examine both:
case a: x is even.
If x is even, then kx is even, which means y is even (since y=kx).
If y is even, then jy is even, which means z is even (since z=jy).
case b: z is even
Since both possible cases yield the same answer to the target question, statement 1 is SUFFICIENT

Statement 2: y is even
If y is even, then jy is even, which means z is even (since z=jy).
Since we can answer the target question with certainty, statement 2 is SUFFICIENT

Answer = D

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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