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Tricky Number Prop

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Source: — Data Sufficiency |
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by shovan85 » Thu Dec 02, 2010 4:24 am
anticipation wrote:If x and y are positive integers and y = √(9 -x) , what is the value of y?
(1) x < 8
(2) y > 1
IMO D

(1) x<8

x and y both positive integers

any integer below 8 and above 0 Only x = 5 satisfies the same. Thus y = 2. (Sufficient)

(2) y>1

x and y both positive integers

Now y^2 where y > 1 can be 4, 9, 16
but y = √(9 -x) => y^2 = 9-x

So only y^2 = 4 will satisfy for a positive integer x and thus y=2. (Sufficient)
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by avigyan710 » Thu Dec 02, 2010 5:06 am
anticipation wrote:If x and y are positive integers and y = √(9 -x) , what is the value of y?
(1) x < 8
(2) y > 1
Problem Stem=> Y =sqrt(9-x).

X and Y are positive integers. It means the value of X and Y cannot be -ve and fraction.

0 is neither positive nor negative integer.

sqrt of 0 is 0.

Stem1=> Only one value of X satisfies the condition. X=5. Y=3. SUFF.
Stem2=> Since Y is greater than 1 and it is not negative, X can only be 5. SUFF.

Answer is D.

What is the OA?
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