-
turbocharge2010
- Newbie | Next Rank: 10 Posts
- Posts: 1
- Joined: Fri Jan 01, 2010 11:15 pm
If x^2 + y^2 = 29, what is the value of (x-y)^2?
1) xy = 10
2) x = 5
OA [spoiler]= A[/spoiler]
So I understand that statement 1 is sufficient. But why isn't statement 2 sufficient? The answer explains that it is because statement 2 doesn't tell us what Y is. Why not? Why can't we substitute x=5 into the equation x^2 + y^2 = 29 to have y = 2? Kindly advise. Thanks!
1) xy = 10
2) x = 5
OA [spoiler]= A[/spoiler]
So I understand that statement 1 is sufficient. But why isn't statement 2 sufficient? The answer explains that it is because statement 2 doesn't tell us what Y is. Why not? Why can't we substitute x=5 into the equation x^2 + y^2 = 29 to have y = 2? Kindly advise. Thanks!
