Evaluate statement 1: 2x - 3y = -2
based on the given information, Y is greater than X. Else the resulting value would not be negative.
so, the question is -2 < X sqr. Given that X sqr will always be positive, statement A answers the question.
Evaluate statement 2:x>2 and y>0
pick some numbers:
If x=3; y= 5;
2(3) - 3(15) < 9
6 - 45 < 9
-39 < 9 - yes
If x=3; y = 1;
2(3) - 3(1) < 9
6 - 3 < 9
3 < 9
hence statement B answers the question.
The final answer to this question is D
OG 11 porblem 119
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Is 2x-3y< X^2
From (1) we have
-2<x^2
This is sufficient as the square of a number will always be +ve
From (2)
The given equation can be written as
is x^2-2x+3y > 0 ?
is x(x-2) + 3y > 0 ?
If x>2
then x(x-2) will be greater than 0
And if y>0,3y will be greater than 0
Hence sufficient
Therefore D
From (1) we have
-2<x^2
This is sufficient as the square of a number will always be +ve
From (2)
The given equation can be written as
is x^2-2x+3y > 0 ?
is x(x-2) + 3y > 0 ?
If x>2
then x(x-2) will be greater than 0
And if y>0,3y will be greater than 0
Hence sufficient
Therefore D












