guerrero wrote:Buster leaves the trailer at noon and walks towards the studio at a constant rate of B miles per hour. 20 minutes later, Charlie leaves the same studio and walks towards the same trailer at a constant rate of C miles per hour along the same route as Buster. Will Buster be closer to the trailer than to the studio when he passes Charlie?
(1) Charlie gets to the trailer in 55 minutes.
(2) Buster gets to the studio at the same time as Charlie gets to the trailer.
Need help . Please explain the approach
OA B
Pictorial representation of situation
B------------------------X------------------------C
Trailer<----------->meeting point<------------->Studio
question is asking when Buster meet Charlie, i.e. point X, then the distance BX<CX.
statement 1:-
We know charlie took 55 min, but we don't know anything about the speed of Buster.
Not sufficient.
statement 2:-
Now we know if buster took t min to reach studio then charlie took t+20 min. Now we don't have ratio of their speed. so we have 2 unknown , distance and time.
so not sufficient.
combining two statement.
we know charlie took 55 min and buster took 35 min. what ever may be the Distance we can calculate their speed ratio so we can solve this problem.
Note:- Although, I'm doing showing the further calculation but knowing this is a DS question I don't need to do it.
TS --> distance between Trailer and Studio
B/C = (TS/35)/(TS/55)=> B:C = 11:7{ratio of speed of Buster and Charlie.}
So time taken by Buster and charlie to meet a point X.
TS/(11a + 7a) = TS/18a
distance traveled by Buster in TS/18a = 11a * TS/18a =11*TS/18.
BX = 11*TS/18
CX = 7*TS/18
BX > CX.
Hope it helps.
Cheers,
Hemant
Answer is C.
I'm no expert, just trying to work on my skills. If I've made any mistakes please bear with me.
