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by dunkin77 » Mon Jun 18, 2007 3:25 pm
Is lxl< 1?
(1) lx + 1l = 2lx - 1l
(2) lx - 3l &#8800; 0


I thought was B but the answer is different... can anyone help?
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by jayhawk2001 » Mon Jun 18, 2007 3:45 pm
dunkin77 wrote:Is lxl< 1?
(1) lx + 1l = 2lx - 1l
(2) lx - 3l &#8800; 0


I thought was B but the answer is different... can anyone help?
Is it C ?

1 - insufficient. Either x = 3 or x = 1/3 satisfies the condition.

Taking the positive values,
x + 1 = 2x - 2 or x=3

Taking one side as negative,
x + 1 = -2x + 2 or x = 1/3

2 - insufficient. Take x = 0.5 and x = 1.5. Both satisfy the condition.

(1) and (2) together tell us that x not equal to 3. So, x = 1/3 and hence
is sufficient.
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by 800GMAT » Mon Jun 18, 2007 4:45 pm
Is lxl< 1
In other words, Is -1<x<1?

(1) lx + 1l = 2lx - 1l
Squaring both sides and solving for x
x=3 and x=1/3

(2) lx - 3l &#8800; 0
Just says x is not equal to 3
Since x can have infinitely many values, (2) is insuff

(1) and (2), since x is not equal to 3, x=1/3..Suff

Hence C
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by dunkin77 » Tue Jun 19, 2007 12:42 am
Yes, OA is C. Thank you!
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