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radhika1306
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Is the ANS A?
t(n+1) = tn/2
Stmt 1 - t3 = 1/4 => t4 = 1/8 => t5 = 1/16 SUFF
Stmt 2 -> t1-t5 = 15/16 => does not give info for t1 => NOT SUFF
22 set 16
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Source: Beat The GMAT — Data Sufficiency |
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ratindasgupta
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1) If t3 = 1/4. we can work out t4 and then t5. So SUFFradhika1306 wrote:In the sequence of nonzero numbers t1, t2, t3, …, tn, …, tn+1 = tn / 2 for all positive integers
n. What is the value of t5?
(1) t3 = 1/4
(2) t1 - t5 = 15/16
2) t1 - t5 = 15/16. Assume t1 as x. So t5 is x/16. So x - x/16 = 15/16. So x = 1. So SUFF
Answer is D
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ratindasgupta
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I have not calculated t5 as 15x/16. if t1 = x, the t2 = x/2, t3 = x/4, t4 = x/8 and t5 = x/16.kajcha wrote:Ratin, for second stmt you calculated t5 = 15x/16. Why did you assume x = 1?
So the equation stands as x - x/16 = 15/16. By cross multiplying, you get the valueof x = 1.
Hope this clears it Kajcha.
Yup, it does.. got confused.. thanksratindasgupta wrote:I have not calculated t5 as 15x/16. if t1 = x, the t2 = x/2, t3 = x/4, t4 = x/8 and t5 = x/16.kajcha wrote:Ratin, for second stmt you calculated t5 = 15x/16. Why did you assume x = 1?
So the equation stands as x - x/16 = 15/16. By cross multiplying, you get the valueof x = 1.
Hope this clears it Kajcha.
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ratindasgupta
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- Joined: Mon Jun 11, 2007 10:32 pm
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