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Source: — Data Sufficiency |
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by ov25 » Tue Dec 14, 2010 5:18 pm
i) prolly undisputed - SUFF
ii) 20 dogs (20+b) more than birds b;
1/3p = 20+b
1/5p = b
2/15p=20
p=150

so 50 pets are dogs. SUFF
D

sorry for the confusion !CORRECTED!
Last edited by ov25 on Tue Dec 14, 2010 9:30 pm, edited 1 time in total.
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by GHong14 » Tue Dec 14, 2010 8:34 pm
Care two explain how you trasnlated the second statement and solved?
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by ov25 » Tue Dec 14, 2010 9:34 pm
I just corrected and posted soln. thanks.
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by naremnaresh » Tue Dec 14, 2010 9:39 pm
let x be the total number of animals.
x/5 is the number of birds.
x/3 is the numbers of dogs

1.from first statment x/5 = 30.
so x = 30 *5 = 150 is the total number of pets.
dogs are 1/3 of 150 = 50 dogs.

2. from second statement.

dogs = birds + 20
x/3 = x/5 + 20
x/3 - x/5 = 20
2x/15 = 20
2x = 300
x =150

total number of pets = 150.
dogs are 1/3 of 150 = 50 dogs.

so Each statement alone is sufficient.
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