BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

manhatan 5

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Legendary Member
Posts: 789
Joined: Sun May 06, 2007 1:25 amFollowed by: 6 members
Location: Southern California, USA
Thanked: 15 times
by resilient » Sun Feb 17, 2008 11:21 pm
x, y, and z are consecutive integers, and x < y < z. What is the average of x, y, and z?

(1) x = 11

(2) The average of y and z is 12.5.

qa is d i chose c
Appetite for 700 and I scraped my plate!
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Data Sufficiency |
Senior | Next Rank: 100 Posts
Posts: 74
Joined: Tue Sep 25, 2007 7:58 am
Thanked: 4 times

Re: manhatan 5

by joshi.komal » Tue Feb 19, 2008 2:13 am
Enginpasa1 wrote:x, y, and z are consecutive integers, and x < y <z> [x + (x+1) +(x+2)]/3
=> [3x + 3]/3
=> x+1
NOw your rephrased question is:
What is x?

Any stmt. answering the this question is sufficient

(1) x = 11 SUFFICIENT :ELIMINATE choices B,C,E

(2) The average of y and z is 12.5. Solve it: y = x+1 and Z = x+2
(y+z)/2 = 12.5
=>[(x+1)+(x+2)]/2 = 12.5
SUFFICIENT you can get the value of x

Hence the answer is D



Hope it helps

Thanks
Komal
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1