Viren1808 wrote:Q. Is (x+1)/(x-3) < 0 ?
(1) -1 < x < 1
(2) x^2 - 4 < 0
Request you to kindly provide some trick to tackle such problems during the test in fastest possible ways.
Determine the
critical points: the values of x that will make the numerator or the denominator equal to 0.
The critical points here are x=-1 and x=3.
These are the only values of x where (x+1)/(x-3) is equal to 0 or is undefined.
Thus, when x is any other value, (x+1)/(x-3) will be either greater than or less than 0.
To determine the range of x, test one value to the left and right of each critical point.
x < -1.
If x=-2, we get:
(-2+1)/(-2-3) < 0.
1/5 < 0.
Doesn't work.
x < -1 is not part of the range.
-1 < x < 3.
If x=0, we get:
(0+1)/(0-3) < 0.
-1/3 < 0.
This works.
-1<x<3 is part of the range.
x > 3.
If x=4, we get:
(4+1)/(4-3) < 0.
5 < 0.
Doesn't work.
x > 3 is not part of the range.
Question rephrased: Is -1 < x < 3?
Statement 1: -1 < x < 1.
Thus, x must be between -1 and 3.
SUFFICIENT.
Statement 2: x²<4.
Since it's possible that x = 0 (which is between -1 and 3) or that x = -3/2 (which is not between -1 and 3), INSUFFICIENT.
The correct answer is
A.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at
[email protected].
Student Review #1
Student Review #2
Student Review #3