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Please provide solutions for these PS questions.

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by snakedoc » Wed Dec 14, 2011 9:38 am
1) n and y are positive integers and 450y = n3, which is an integer?
y / 3 * 22 * 5
y / 32 * 2 * 5
y / 3 * 2 * 52
a. None
b. I
c. II
d. III
e. I, II, III


2) If x4 + y4 = 100, the greatest possible value of x is between
a. 0 and 3
b. 3 and 6
c. 6 and 9
d. 9 and 12
e. 12 and 15
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Source: — Problem Solving |

by GMATGuruNY » Wed Dec 14, 2011 9:50 am
If n and y are positive integers and 450y = n³, which of the following must be an integer?

I. y/(3 x 2² x 5)

II. y/(3² x 2 x 5)

III. y/(3 x 2 x 5²)

a. None
b. I only
c. II only
d. III only
e. I, II, and III
450y is the cube of an integer.

When we prime-factorize the cube of an integer, we get 3 (or a multiple of 3) of every prime factor:
8 is the cube of an integer because 8 = 2³ = 2*2*2.
27 is the cube of an integer because 27 = 3³ = 3*3*3.

Thus, when we prime-factorize 450y, we need to get at least 3 of every prime factor:
450y = 2 * 3² * 5² * y

Since 450 provides only one 2, two 3's, and two 5's, y must provide the missing prime factors. We need y to provide two more 2's, one more 3, and one more 5.
Thus, the smallest possible value is y = 2² * 3 * 5.

Onto the answer choices:

I. y/(3 x 2² x 5)
(2² * 3 * 5)/(3 x 2² x 5) = 1. The smallest possible value of y yields an integer.
Eliminate every answer choice that does not include I.
Eliminate A, C and D.

II. y/(3² x 2 x 5)
(2² * 3 * 5)/(3² x 2² x 5) = 1/3. Not an integer.
Eliminate every remaining answer choice that includes II.
Eliminate E.

The correct answer is B.
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by Anurag@Gurome » Wed Dec 14, 2011 7:56 pm
snakedoc wrote:2) If x4 + y4 = 100, the greatest possible value of x is between
a. 0 and 3
b. 3 and 6
c. 6 and 9
d. 9 and 12
e. 12 and 15
x will be maximum when y is minimum.
Minimum value of y can be 0
So, x^4 = 100 implies 3^4 = 81 and 4^4 = 256, which means x should be greater than 3 and less than 4.

The correct answer is B.
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by snakedoc » Thu Dec 15, 2011 3:39 am
Thanks Guys :)
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