A little help...

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adsuper7: Newbie | Next Rank: 10 Posts; Posts: 5; Joined: Fri Sep 10, 2010 11:45 pm

by adsuper7 » Fri Oct 14, 2011 8:47 pm

Having a bit of trouble solving this problem.

xy+2xy(1+y)2y

A. xy(2y+1)^2
B. (2xy+1)(2xy-1)
C. (2x+y)^2
D. (x+2y)^2
E. y(x-2y)^2

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Source: Beat The GMAT — Problem Solving | Fri Oct 14, 2011 8:47 pm

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Anurag@Gurome: GMAT Instructor; Posts: 3835; Joined: Fri Apr 02, 2010 10:00 pmFollowed by: 523 members; Location: Milpitas, CA; Thanked: 1854 times; GMAT Score:770

by Anurag@Gurome » Fri Oct 14, 2011 8:55 pm

adsuper7 wrote:xy+2xy(1+y)2y

I guess the problem is to find the equivalent expression or the factorized form of the given expression. Anyways, here is the solution...

# xy + 2xy(1 + y)2y
= xy[1 + 2(1 + y)2y]
= xy[1 + 4y + 4yÂ²]
= xy(2y + 1)Â²

The correct answer is A.

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zooki: Junior | Next Rank: 30 Posts; Posts: 29; Joined: Fri Oct 14, 2011 10:15 amFollowed by: 1 member; Thanked: 4 times

by zooki » Sat Oct 15, 2011 5:59 am

in the original expression the power of x is 1. Only Answer A satisfies this.

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sam2304: Legendary Member; Posts: 1239; Joined: Tue Apr 26, 2011 6:25 amFollowed by: 26 members; Thanked: 233 times; GMAT Score:680

by sam2304 » Sat Oct 15, 2011 6:01 am

That's awesome. Easier than solving. Thanks zooki.

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adsuper7: Newbie | Next Rank: 10 Posts; Posts: 5; Joined: Fri Sep 10, 2010 11:45 pm

by adsuper7 » Sat Oct 15, 2011 9:18 am

Thanks all!

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HeyArnold: Senior | Next Rank: 100 Posts; Posts: 31; Joined: Sun Jul 31, 2011 10:55 amFollowed by: 1 member

by HeyArnold » Sun Oct 16, 2011 7:31 am

It would not take too long to just plug in #'s here either.

x = 2
y = 1

(2x1) + 2(2x1)(1+1)2(1) = 18

only A. = 18

(2x1)(2x1 + 1)^2 = 2(3)^2 = 18

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HeyArnold: Senior | Next Rank: 100 Posts; Posts: 31; Joined: Sun Jul 31, 2011 10:55 amFollowed by: 1 member

by HeyArnold » Sun Oct 16, 2011 7:33 am

It would not take too long to just plug in #'s here either.

x = 2
y = 1

(2x1) + 2(2x1)(1+1)2(1) = 18

only A. = 18

(2x1)(2x1 + 1)^2 = 2(3)^2 = 18

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