I/K > 0

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Source: — Data Sufficiency |

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by Frankenstein » Sun Jun 12, 2011 2:50 am
Hi,
From(1): 1/(k-1) > 0. So, k-1>0 =>k > 1. So, k is positive. 1/k > 0
sufficient

From(2): 1(k+1)>0. So, k+1>0 =>k>-1
for -1<k<0, 1/k <0
for k>0, 1/k>0
Insufficient

Hence, A
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by HSPA » Sun Jun 12, 2011 2:59 am
+1 for A
First take: 640 (50M, 27V) - RC needs 300% improvement
Second take: coming soon..
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HSPA.