rupsk wrote:Traveling at three-fourth of his normal speed John reaches his office late by 16 minutes. Find the time taken by John to reach his office if he travels at his normal speed.</p>
A. 45 min
B. 48 minutes
C. 40 minutes
D. 50 minutes
E. 55 minutes
I had solved by looking at the answer is there any other way?
Traveling at 3/4 the speed = traveling for 4/3 the time.
Since the normal time is increased by 1/3:
16 = (1/3)t
t = 48.
The correct answer is
B.
We also could plug in the answers:
Answer choice B: 48 minutes.
Let r = 4 miles per minute.
Then d = r*t = 4*48 = 192 miles.
3/4 the rate = (3/4)*4 = 3 miles per minute.
Time at the slower rate = d/r = 192/3 = 64 minutes.
Difference in time = 64-48 = 16. Success!
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