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What is the area of the above triangle?

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by Max@Math Revolution » Thu Sep 06, 2018 12:29 am

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[Math Revolution GMAT math practice question]9.6

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What is the area of the above triangle?

1) y=z
2) y+z=10
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Source: — Data Sufficiency |

by fskilnik@GMATH » Thu Sep 06, 2018 5:01 am
Max@Math Revolution wrote:[Math Revolution GMAT math practice question]

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What is the area of the above triangle?

1) y=z
2) y+z=10
Let´s go straight to (1+2) . Reason: if we are able to (geometrically) BIFURCATE both statements together immediately, we save a significant amount of time!

The areas of both triangles presented are different, and both triangles satisfy both statements. We are done! Answer: [spoiler]___(E)___[/spoiler]

This solution follows the notations and rationale taught in the GMATH method.

Regards,
fskilnik.

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Fabio Skilnik :: GMATH method creator ( Math for the GMAT)
English-speakers :: https://www.gmath.net
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by Max@Math Revolution » Sun Sep 09, 2018 5:18 pm
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Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.

Since we have 3 variables (x, y and z) and 0 equations, E is most likely to be the answer. So, we should consider conditions 1) & 2) together first. After comparing the number of variables and the number of equations, we can save time by considering conditions 1) & 2) together first.

Conditions 1) & 2)

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If x = y = z = 5, then the triangle is equilateral, and its area is (√3/4)*52 = (25/4) √3.
If x = 6 and y = z = 5, then the area of the triangle is (1/2)6*4 = 12.
Since the answer is not unique, conditions 1) & 2) are not sufficient, when taken together.

Therefore, E is the answer.
Answer: E

In cases where 3 or more additional equations are required, such as for original conditions with "3 variables", or "4 variables and 1 equation", or "5 variables and 2 equations", conditions 1) and 2) usually supply only one additional equation. Therefore, there is an 80% chance that E is the answer, a 15% chance that C is the answer, and a 5% chance that the answer is A, B or D. Since E (i.e. conditions 1) & 2) are NOT sufficient, when taken together) is most likely to be the answer, it is generally most efficient to begin by checking the sufficiency of conditions 1) and 2), when taken together. Obviously, there may be occasions on which the answer is A, B, C or D.
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