37. Tossing two dices at random, what is the probability that the sum of numbers upside is greater than 9?
(A)2/9 (B) 7/36 (C) 5/36 (D) 1/6 (E) 1/9
[spoiler]OA: D[/spoiler]
This problem look pretty straightforward at first. These are the possibilities for dices: 1,2,3,4,5,6. The only dices faces that will sum to a number greater than 9 are 5 and 6. I thought since there is 2/6 ways of getting 5 or 6 on one die, then (1/3)*(1/3)=1/9 would be my probably of getting a number greater than 9. However, this is incorrect. Can someone explain?
(A)2/9 (B) 7/36 (C) 5/36 (D) 1/6 (E) 1/9
[spoiler]OA: D[/spoiler]
This problem look pretty straightforward at first. These are the possibilities for dices: 1,2,3,4,5,6. The only dices faces that will sum to a number greater than 9 are 5 and 6. I thought since there is 2/6 ways of getting 5 or 6 on one die, then (1/3)*(1/3)=1/9 would be my probably of getting a number greater than 9. However, this is incorrect. Can someone explain?
