((n - 2)^-1)(2 + n)
If n >2 and 2/n is substituted for all instances of n in the above expression, then the new expression will be equivalent to which of the following:
A) (n + 1)(n - 1)^-1
B) -(n + 1)(n - 1)^-1
C) -(n - 1)(n + 1)^-1
D) ((2 + n)^-1)(n - 2)
E) ((n - 2)^-1)(2 + n)
[spoiler]OA: B i originally chose 4 for n, thinking that 1/2 would be easier to work with than 2/3 (in the case of choosing 3) only to find that 4 returns -1 to the original equation and -5/3 for the answer B. Any thoughts on avoiding this sort of issue in the future when picking numbers?
Thanks![/spoiler]
If n >2 and 2/n is substituted for all instances of n in the above expression, then the new expression will be equivalent to which of the following:
A) (n + 1)(n - 1)^-1
B) -(n + 1)(n - 1)^-1
C) -(n - 1)(n + 1)^-1
D) ((2 + n)^-1)(n - 2)
E) ((n - 2)^-1)(2 + n)
[spoiler]OA: B i originally chose 4 for n, thinking that 1/2 would be easier to work with than 2/3 (in the case of choosing 3) only to find that 4 returns -1 to the original equation and -5/3 for the answer B. Any thoughts on avoiding this sort of issue in the future when picking numbers?
Thanks![/spoiler]
