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EMPLOYED STUDENTS??

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by amising6 » Fri Jul 16, 2010 3:10 pm
enriqueta26 wrote:COULD SOMEONE HELP ME??

HOW MANY OF 42 PEOPLE ARE EMPLOYED STUDENTS??

1)29 OF 42 PEOPLE ARE EMPLOYED

2) 24 OF 42 PEOPLE ARE STUDENTS

ANSWER E

THANK YOU!!
HOW MANY OF 42 PEOPLE ARE EMPLOYED STUDENTS

statement 1) 29 OF 42 PEOPLE ARE EMPLOYED
it doesnt ell us wether they are student only or someon else
doesnt help s insufficient
2) 24 OF 42 PEOPLE ARE STUDENTS
this only tell us total number of student but no info about how many out of this 24 are employed .
so stement 2 is insufficient
combining 1 and 2 we have 29 people are employeed and 24 are student so it can be 24 student are there and al of them are employeed or 20 student are emplyeed .it can be any number less than or equal to 24 student who are employeed so no help
thus answer will be E cannot be solved
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by Patrick_GMATFix » Fri Jul 16, 2010 3:35 pm
Enriqueta, please don't post in ALL CAPS. When you write the Official Answer in your post, please highlight it and press the SPOILER button to hide the answer from people who want to attempt the question before they see the right answer.

Ok, on to your question:

There are 42 people. Some people are students, some people are employed. We want to find out how many belong to both groups. Keep in mind that some may belong to neither group.

Since this is an overlapping group question, we could use the formula group1+group2+neither-both=total --> 42=employed+students+neither-both. We're looking for both.

(1) employed=29. put that in the equation to get 42=29+students+neither-both. We cannot solve for both. NOT SUFFICIENT

(2) students=24. put that in the equatino to get 42=employed+24+neither-both. We cannot solve for both. NOT SUFFICIENT

To merge statements, put all the known data in the equation. 42=29+24+neither-both. Because we don't know the value of neither, we cannot solve for both. NOT SUFFICIENT

The answer is E. For a more detailed discussion, or to watch the step by step video solution, see GMATPrep Question 1347. To practice similar questions, set topic='Sets & Groups' and difficulty='500-600' in the Drill Generator

Hope that helps,
-Patrick
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by enriqueta26 » Fri Jul 16, 2010 4:24 pm
thank you so much!!, awesome!!!!
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by Patrick_GMATFix » Fri Jul 16, 2010 4:51 pm
You got it buddy.
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