Juggernaut_86 wrote:A provision store will purchase three cans of worms. There are two models of cans available, Model 1 and Model 2, each of which is available in four colors: yellow, white, gray, and gold. How many different combinations of the three cans can the store select if all the cans are to be different colors?
a) 24
b) 32
c) 48
d) 60
e) 192
Seeking explanation....Thanks!
2 model options available:
Number of model options for the first can = 2.
Number of model options for the second can = 2.
Number of model options for the third can = 2.
To combine the options for each can, we multiply:
2*2*2 = 8.
4 colors available:
Number of ways to choose 3 colors from 4 choices = 4C3 = 4.
To combine our model options with our color options, we multiply:
8*4 = 32.
The correct answer is
B.
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