BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Quadratic equation - Parabola

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Junior | Next Rank: 30 Posts
Posts: 18
Joined: Fri Jan 15, 2010 4:18 pm
by hemanthquartz1 » Sun Jan 17, 2010 3:09 am
Hello Guru's

Please help me solve this question.

1.On the graph When x=1/2,y=2;and when x=1,y=1.The graph is symmetric with respect to the vertical line at x=2.According to the graph,when x=3,y=

a) -1
b)-1/2
c)0
d)1/2
e)1

2. Could you also find out the parabolic equation?

Finding the equation has been driving me crazy for few hours now to . I have used this equation Y=Ax2+Bx+C but not able to solve it. Please help.

Thanks
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
Junior | Next Rank: 30 Posts
Posts: 18
Joined: Fri Jan 15, 2010 4:18 pm

by hemanthquartz1 » Sun Jan 17, 2010 6:16 pm
Hello,

I am still waiting for the reply. Could some please try to solve this?
Could someone solve the equation for the points?

Thanks
Hemanth
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 98
Joined: Mon Nov 23, 2009 2:30 pmFollowed by: 1 member
Thanked: 26 times

by ace_gre » Mon Jan 18, 2010 11:03 pm
Hi, I googled for equation for parabola and found that I need to use one more equation to solve..(axis of symmetry x = -b/2a)

https://www.mathwarehouse.com/geometry/p ... x-form.php

y = ax^2 + bx + c

when x =1/2 , y = 2 ,
8 = a + 2b + 4c--------(1)

when x= 1, y =1,
1= a + b + c-----------(2)

x = 2 = -b / 2a
b = -4a---------------(3)

Multiply (2) by 4 and subtract from (1)

4 = -3a -2b
4= -3a -2(-4a)
4 = 5a
a = 4/5
Substitute a = 4/5 in (3)
b = -16/5

Substitute the above in (1), c= 17/5
Parabola equation y = 4/5 x^2 - 16/5 x + 17/5
when x=3, y =1

IMO E y=1 , parabola equation 5y= 4x^2 - 16x + 17.

Is this correct? Please post OA.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Junior | Next Rank: 30 Posts
Posts: 18
Joined: Fri Jan 15, 2010 4:18 pm

by hemanthquartz1 » Tue Jan 19, 2010 8:13 am
Thank you so much for the reply and for the link.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 16207
Joined: Mon Dec 08, 2008 6:26 pmFollowed by: 1268 members
Location: Vancouver, BC
Thanked: 5254 times
GMAT Score:770

by Brent@GMATPrepNow » Wed Jan 20, 2010 6:49 pm
hemanthquartz1 wrote:Hello Guru's

Please help me solve this question.
1.On the graph When x=1/2,y=2;and when x=1,y=1.The graph is symmetric with respect to the vertical line at x=2.According to the graph,when x=3,y=
a) -1
b)-1/2
c)0
d)1/2
e)1
2. Could you also find out the parabolic equation?
Finding the equation has been driving me crazy for few hours now to . I have used this equation Y=Ax2+Bx+C but not able to solve it. Please help.
Thanks
I can assure you that you don't need to know how to find the equation of a parabola on the GMAT.
The important point to recognize here is that parabolas are symetrical about an axis. See image.
Image
Brent Hanneson - Creator of GMATPrepNow.com
Image
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1