taneja.niks wrote:p and q are different two-digit prime numbers with the same digits, but in reversed order. What is the value of the larger of p and q?
(1) p + q = 110
(2) p - q = 36
what shall be he right answer??
let p=10a+b;
q=10b+a;
1) p+q=110; 10a+b+10b+a=110, 11(a+b)=110; a+b=10; different numbers are possible for different values of a and b, for example (1,9),(2,8),(3,7),(4,6)..!!!
5,5 is not possible because p and q are two different numbers.
hence a alone is not sufficient to answer the question.
2)p-q=36; 10a+b-10b-a=36; 9(a-b)=36, a-b=4; different values of a and b that are possible are,(5,1),(6,2),(7,3),(8,4),(9,5)..!!! therefore 2 alone is also not sufficient to answer the question.!!!
now combine 1 and 2 we have only one common value that is (3,7)..!!
therefore answer should be
C...!!!
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