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Consecutive Integer!

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Source: — Data Sufficiency |
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by selango » Tue Aug 03, 2010 10:13 am
F=Product of first 30 integers.30!

D is a positive integer.

stmt1,

10^D is a factor of F.

To find the number of 10's we must need to find number of 5's in 30!

30/5+30/25=6+1=7

Number of 10's in 30!=7

10 is a factor of F.

100 is also a factor of F.

We don't know about D.

Insuff

stmt2,

D>6

Still there are many values of D that can be a factor of F.

Insuff

Combining 1 and 2,

D>6.Do D=7

-->10^7 is a factor of F.

Suff.

Pick C

F has 7 zeroes only..Am I missing something?
--Anand--
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