Apologies for raising the doubt, are you sure you have posted the correct question?
As per the given fact, x=5k+2, where k is an integer.
Now, only x/17 can result into an integer when k=3
division
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pankajks2010
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manpsingh87
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x=5k+2; when k=3; x=17 which is divisible by 17,2logj wrote:If when a certain integer x is divided by 5
the reminder is 2,then all the following could
also be an integer except
A X/17
B X/11
C X/10
D X/6
E X/3
when k=15, x=77, which is divisible by 11;
when k=2, x=12 which is divisible by 6;
when k=2, x=12 which is divisible by 3,
hence answer should be C, although there is no need to go for all these steps,we can straight away reason that last digit of 5k+2 will be either 2 or 7, depending upon whether k is even or odd, hence it will never be divisible by 10..!!!
i hope it helps...!!!
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GMATGuruNY
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Make a list of values that satisfy the conditions given.2logj wrote:If when a certain integer x is divided by 5
the reminder is 2,then all the following could
also be an integer except
A X/17
B X/11
C X/10
D X/6
E X/3
On the GMAT, this problem likely would be restricted to positive integers.
When X is divided by divisor D, the remainder is R means that the smallest possible value of X is R.
To generate the other possible values of X, just keep adding multiples of the divisor D to R.
In the problem above:
The smallest possible value of X is R=2.
Adding multiples of the divisor D=5 to R=2, we get the following list:
2,7,12,17,22,27...
Each of the numbers above is 2 more than a multiple of 5; thus, when each number is divided by 5, R=2.
Now compare the numbers in the list to the expressions in the answer choices:
12 is a multiple of 6 and of 3.
Eliminate D and E.
17 is a multiple of 17.
Eliminate A.
22 is a multiple of 11.
Eliminate B.
The correct answer is C.
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Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
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For more information, please email me (Mitch Hunt) at [email protected].
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