BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

average value of set > median of set ?

Expert replies
by gmatjeet » Sun Jun 05, 2011 8:02 am
In a set of 5 numbers if the largest number is 3 more than the median, Is the average value of set > median of set ?

1. All the numbers are different.

2. The median is 10 more than the smallest number in the set.

I tried this question and am confused as my answer is coming out to E but on the forum, everyone is giving the answer as B
-> If the median is considered to be always positive, then the answer should be B. But if we consider the median to be either positive or answer then my answer is E. Can someone please help.
Join the discussion
Source: — Data Sufficiency |

by cans » Sun Jun 05, 2011 8:16 am
a,b,c,d,e numbers in ascending order
e=c+3
(a+b+c+d+e)>5c?? ->a+b+d>3c-3
1. All numbers are different. insufficient. (take a.b small enough and c large enough and d=c,inequality won't hold. but if you take a=b=c=d,0>-3 true)
2. c=a+10
b+d>2c+7
max value of d=c+3 (which is same as largest number)
min value of d=c (same as median)
if we take min d,b>c+7 not true
if we take max d, b>c+4 not true
Thus avg is always less than mean. Sufficeint
IMO B
If my post helped you- let me know by pushing the thanks button ;)

Contact me about long distance tutoring!
[email protected]

Cans!!
Join the discussion

by Frankenstein » Sun Jun 05, 2011 8:24 am
Hi,
As you are aware that (1) is not sufficient, I will skip that
From(2): Let the numbers in increasing order be a,b,c,d,e
i.e. c-10,b,c,d,c+3, where c-10<=b<=c and c<=d<=c+3
Minimum value of sum of the numbers is when b=c-10 and d=c
Sum = 5c-17. So mean = c-3.4
Maximum value of sum of the numbers is when b=c and d=c+3
Sum = 5c-4. So, mean is c-0.8
In both the cases mean < median

Hence B
Cheers!

Things are not what they appear to be... nor are they otherwise
Join the discussion