BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Work problem - Janice can mow the lawn . . .

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 16207
Joined: Mon Dec 08, 2008 6:26 pm
Location: Vancouver, BC
Thanked: 5254 times
Followed by:1268 members
GMAT Score:770

Work problem - Janice can mow the lawn . . .

by Brent@GMATPrepNow » Tue Jan 27, 2009 3:15 pm
Janice can mow the lawn 50 minutes faster than it takes Rita to mow the same lawn. One day, after mowing the lawn by herself for 20 minutes, Janice quits. If it takes Rita 30 minutes to mow the remaining lawn, how many minutes would it take Janice to mow the entire lawn on her own?
(A) 20 sqrt2
(B) 10 sqrt10
(C) 4 sqrt70
(D) 15 sqrt5
(E) 16 sqrt5
Please note that this is not an official GMAT question; it’s my attempt to create difficult (650+ level) GMAT-style questions for this forum.
Brent Hanneson - Creator of GMATPrepNow.com
Image
Top
Source: — Problem Solving |
Newbie | Next Rank: 10 Posts
Posts: 3
Joined: Sun Aug 17, 2008 11:14 pm
Location: Seattle

by sssudhak » Tue Jan 27, 2009 11:00 pm
Answer is B 10 sqrt 10.
Is that right?
Top
Senior | Next Rank: 100 Posts
Posts: 31
Joined: Thu Sep 25, 2008 6:10 pm
Thanked: 2 times

by chintudave » Tue Jan 27, 2009 11:52 pm
Let the time taken by J to mow the lawn is x.
Then, time taken by R is x + 50

In the first 20 minutes, the fraction of lawn mowed by J is 20/x

So fraction of lawn remaining for R is (1 - 20/x)

The time taken by R to mow the remaining lawn would be a product of
1. The fraction of lawn remaining
2. Time taken to mow the complete lawn.

i.e.
(1 - 20x)(x + 50) = 30
(x -20)(x + 50) = 30x
x2 + 30x - 1000 = 30x
x2 = 1000
x = 10 sqrt (10)

Hence B!
Top

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 16207
Joined: Mon Dec 08, 2008 6:26 pm
Location: Vancouver, BC
Thanked: 5254 times
Followed by:1268 members
GMAT Score:770

by Brent@GMATPrepNow » Wed Jan 28, 2009 7:53 am
Nice work - the answer is B.
Here's my solution as well:

Let J = total number of minutes it takes Janice to mow the entire lawn
If Janice can mow the lawn 50 minutes faster than it takes Rita, we can conclude that it takes Rita J+50 minutes to mow the lawn

So, after 1 minute, the fraction of the lawn that Janice will have mowed is 1/J. After 20 minutes, the fraction of the lawn that Janice will have mowed is 20/J
Similarly, after 1 minute, the fraction of the lawn that Rita will have mowed is 1/(J+50). After 30 minutes, the fraction of the lawn that Rita will have mowed is 30/(J+50)

We can create the equation: fraction of lawn mowed by Janice + fraction of lawn mowed by Rita = 1
This means that 20/J + 30/(J+50) = 1
Multiply both sides by J(J+50) to get: 20J + 1000 + 30J = J^2 + 50J
Simplify to get: J^2 = 1000
This means J=sqrt(1000) =10sqrt10
Answer: B
Brent Hanneson - Creator of GMATPrepNow.com
Image
Top
Post new topic Post Reply
• Page 1 of 1