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OG Quantitative Q. 60

Expert replies
by aj84038 » Tue Feb 10, 2009 10:55 am
Hi Guys,

Can you help me on this one please, I really don't get the rational behind this question (I even think that the answer provided is wrong).

Q. When N is divided by T, the quotient is S and the remainder is V. Which of the following expressions is equal to N ?

A) ST
B) S + V
C) ST + V
D) T(S+V)
E) T(S-V)

OA: C

For me it is : D and I really don't get why. I have used numbers and I still think that my answer is the right one.

Thanks a lot for your help
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Source: — Problem Solving |

by dmateer25 » Tue Feb 10, 2009 11:11 am
N/T = S + V/T

Now multiply both sides by T

N = ST + V
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Re: OG Quantitative Q. 60

by Stuart@KaplanGMAT » Tue Feb 10, 2009 3:25 pm
aj84038 wrote:Hi Guys,

Can you help me on this one please, I really don't get the rational behind this question (I even think that the answer provided is wrong).

Q. When N is divided by T, the quotient is S and the remainder is V. Which of the following expressions is equal to N ?

A) ST
B) S + V
C) ST + V
D) T(S+V)
E) T(S-V)

OA: C

For me it is : D and I really don't get why. I have used numbers and I still think that my answer is the right one.

Thanks a lot for your help
Let's pick numbers

if N = 14and T = 4, then we have:

14/4 = 3 rem2

giving us S = 3 and V = 2

D) 4(3+2) = 4*5 = 20... not N
C) 3*4 + 2 = 12 +2 = 14... N.. yay!

You cannot simply multiply both sides by T as you would in a normal equation, because you don't have a normal equation.

We have:

N/T = S remV

We can think of S remV as a mixed fraction. For example, if N/T = 14/4, then:

S remV = 3 + 2/4

(we never reduce fractions when we're dealing with remainders).

So, as dmateer pointed out, our original equation is really:

N/T = S + V/T

and if we multiply both sides by T we get:

N = ST + V
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by ellexay » Wed Feb 11, 2009 6:10 pm
Isn't the formula for remainder questions:

Divisor = Dividend*Quotient + Remainder?

Excuse the terms I wrote if they are not accurate, but you get the idea if you plug the formula in for this problem.

I hope this helps.
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