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by gmatblood » Mon Oct 31, 2011 9:58 am
During a certain season, a team won 80 percent of its
first 100 games and 50 percent of its remaining
games. If the team won 70 percent of its games for
the entire season, what was the total number of
games that the team played?

(A) 180
(B) 170
(C) 156
(D) 150
(E) 105

Why not A and B?
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by shankar.ashwin » Mon Oct 31, 2011 10:08 am
A and B would not satisfy the condition of winning 70% of its total matches.

For A; 80 wins out of first 100 and then 40 out of the remaining 80. Total 120/180 - 66%
For B; 80 wins out of first 100 and then 35 out of the remaining 70. Total 115/170 - 67%

Only D works
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by rijul007 » Mon Oct 31, 2011 10:23 am
80 + x = 70% of (100 + 2x)
80 + x = 70 + 7x/5
2x/5 = 10
x = 5*10/2 = 25

Total no of games = 100 + 2*25 = 150

Option D
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by gmatblood » Mon Oct 31, 2011 10:36 am
shankar.ashwin wrote:A and B would not satisfy the condition of winning 70% of its total matches.

For A; 80 wins out of first 100 and then 40 out of the remaining 80. Total 120/180 - 66%
For B; 80 wins out of first 100 and then 35 out of the remaining 70. Total 115/170 - 67%

Only D works
Oh Yes!! thanks :)
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