BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

circumf of circle

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
User avatar
Master | Next Rank: 500 Posts
Posts: 101
Joined: Tue Oct 27, 2009 8:19 am
Thanked: 4 times
Followed by:2 members

circumf of circle

by g.shankaran » Thu Jun 09, 2011 8:03 am
Square S is inscribed in circle T. If the perimeter of S is 24, what is the circumference of T

1. 6 pi
2. 12 pi
3. 3 sqr (2pi)
4. 6 sqr (2pi)
5. 12 sqr (2 pi)
Top
Source: — Problem Solving |
User avatar
Legendary Member
Posts: 979
Joined: Tue Apr 14, 2009 1:38 am
Location: Hyderabad, India
Thanked: 49 times
Followed by:12 members
GMAT Score:700

by bubbliiiiiiii » Thu Jun 09, 2011 8:08 am
[spoiler]6pi(sqrt)2[/spoiler]
Regards,

Pranay
Top
User avatar
Legendary Member
Posts: 1309
Joined: Mon Apr 04, 2011 5:34 am
Location: India
Thanked: 310 times
Followed by:123 members
GMAT Score:750

by cans » Thu Jun 09, 2011 8:08 am
let side of square=a
then 4a=24 -> a=6
diagonal = 6*root(2) = diameter of circle
thus circumference = diameter*pi
IMO D
If my post helped you- let me know by pushing the thanks button ;)

Contact me about long distance tutoring!
[email protected]

Cans!!
Top
Master | Next Rank: 500 Posts
Posts: 401
Joined: Tue May 24, 2011 1:14 am
Thanked: 37 times
Followed by:5 members

by MBA.Aspirant » Thu Jun 09, 2011 11:47 am
Perimeter = 24, side = 24 /4 = 6

Area of square = 36

1/2 Diagonal^2 = 36

Diagonal= root 72 = 6 root 2

radius = 3 root 2

Circumference = 2 TTr = 2* 3 root 2 * TT = 6 TT root2
Top
User avatar
Master | Next Rank: 500 Posts
Posts: 123
Joined: Tue May 31, 2011 12:26 am
Location: Hyderabad
Thanked: 5 times
Followed by:1 members

by jainnikhil02 » Thu Jun 09, 2011 11:59 am
[spoiler]6pi(root3)[/spoiler]
Nikhil K Jain
____________________

"Life is all about timing" Don't waste your and others time.
Top
User avatar
GMAT Instructor
Posts: 3225
Joined: Tue Jan 08, 2008 2:40 pm
Location: Toronto
Thanked: 1710 times
Followed by:614 members
GMAT Score:800

by Stuart@KaplanGMAT » Thu Jun 09, 2011 12:02 pm
MBA.Aspirant wrote:Perimeter = 24, side = 24 /4 = 6

Area of square = 36

1/2 Diagonal^2 = 36

Diagonal= root 72 = 6 root 2

radius = 3 root 2

Circumference = 2 TTr = 2* 3 root 2 * TT = 6 TT root2
Great solution!

A lesser known formula for the area of a square is:

area = (diagonal^2)/2

which is derived from the Pythagorean theorem (using 45/45/90 ratios).
Image

Stuart Kovinsky | Kaplan GMAT Faculty | Toronto

Kaplan Exclusive: The Official Test Day Experience | Ready to Take a Free Practice Test? | Kaplan/Beat the GMAT Member Discount
BTG100 for $100 off a full course
Top
Post new topic Post Reply
• Page 1 of 1