The answer is indeed Acaramel3536 wrote:If R = 1 + 2xy +x(squared)y(squared)
What is the value of xy
(1) R = 0
(2) x>0
Ans = A
Hi, could you explain me the boldfaced part???parallel_chase wrote:
R=1+2xy+x^2y^2 => (1+xy)^2
Statement I
R=0, therefore (1+xy)^2=0
xy=-1
sq of any non zero no. will be a non zero number onlybhumika.k.shah wrote:Hi, could you explain me the boldfaced part???parallel_chase wrote:
R=1+2xy+x^2y^2 => (1+xy)^2
Statement I
R=0, therefore (1+xy)^2=0
xy=-1
Again this is what i wanted to learn. The concept. THanksthephoenix wrote:
sq of any non zero no. will be a non zero number only
since after squaring the no. is zero -----> the no. itself is zero---->1+xy=0---->xy=-1
Yes, it is safe.HPengineer wrote:I solved this by saying X^2 x Y^2 = A
Then saying A^2 + 2A +1 = 0
(A + 1 ) (A +1)
A = -1 so XY = -1
Is this safe?
