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caramel3536
- Senior | Next Rank: 100 Posts
- Posts: 58
- Joined: Sat Feb 02, 2008 10:13 pm
The answer is indeed Acaramel3536 wrote:If R = 1 + 2xy +x(squared)y(squared)
What is the value of xy
(1) R = 0
(2) x>0
Ans = A
R=1+2xy+x^2y^2 => (1+xy)^2
Statement I
R=0, therefore (1+xy)^2=0
xy=-1
Statement II
x>0
It does not gives us any specific value of x or y or R
Not Sufficient.
Hence A.
















