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Difficult Math Problem #86 - Combinations

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by 800guy » Fri Jan 12, 2007 12:33 am
A photographer will arrange 6 people of 6 different heights for photograph by placing them in two rows of three so that each person in the first row is standing in front of someone in the second row. The heights of the people within each row must increase from left to right, and each person in the second row must be taller than the person standing in front of him or her. How many such arrangements of the 6 people are possible?

A. 5
B. 6
C. 9
D. 24
E. 36

OA coming after some people answer
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by thankont » Fri Jan 12, 2007 12:52 am
I would go for 5

123
456

124
356

125
346

135
246

134
256

thanx
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by Argen » Fri Jan 12, 2007 12:59 am
Is the answer 6?
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OA

by 800guy » Wed Jan 17, 2007 11:32 am
OA:

5 ways

123 124 125 134 135
456 356 346 256 246
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by jaheer » Thu Feb 15, 2007 8:11 pm
Have we missed one more configuration?

135
246

The answer should be 6.

Oops! i counted it twice, ITs 5.
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