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jet1445
- Newbie | Next Rank: 10 Posts
- Posts: 3
- Joined: Mon Jan 15, 2007 8:44 pm
- Location: 1445 Bangrak
Anyone explains to me, Please.
1. On level farmland, two runners leave at the same time from the intersection of two country roads. One runner jogs due north at a constant rate of 8 miles per hour while the second runner jogs due east at a constant rate that is 4 miles per hour faster than the first runner's rate. How far apart, to the nearest mile, will they be after hour ?
(A) 6
(B) 7
(C) 8
(D) 12
(E) 14
Ans. B
2. The rear wheels of a car crossed a certain line 0.5 second after the front wheels crossed the same line. If the centers of the front and rear wheels are 20 feet apart and the car traveled in a straight line at a constant speed, which of the following gives the speed of the car in miles per hour? (5,280 feet = 1 mile)
(A) (20/5280)*{(60^2)/0.5}
(B) (20/5280)*{60/0.5}
(C) (20/5280)*{0.5/(60^2)}
(D) (20*5280)/{(60^2)*0.5}
(E) (20*5280)/{60*0.5}
Ans.A
1. On level farmland, two runners leave at the same time from the intersection of two country roads. One runner jogs due north at a constant rate of 8 miles per hour while the second runner jogs due east at a constant rate that is 4 miles per hour faster than the first runner's rate. How far apart, to the nearest mile, will they be after hour ?
(A) 6
(B) 7
(C) 8
(D) 12
(E) 14
Ans. B
2. The rear wheels of a car crossed a certain line 0.5 second after the front wheels crossed the same line. If the centers of the front and rear wheels are 20 feet apart and the car traveled in a straight line at a constant speed, which of the following gives the speed of the car in miles per hour? (5,280 feet = 1 mile)
(A) (20/5280)*{(60^2)/0.5}
(B) (20/5280)*{60/0.5}
(C) (20/5280)*{0.5/(60^2)}
(D) (20*5280)/{(60^2)*0.5}
(E) (20*5280)/{60*0.5}
Ans.A
:mrgreen:
