help...

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Source: — Problem Solving |

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by gamemaster » Sun Nov 19, 2006 7:20 am
Try this:

3^x-1 = (3^x)/3

3^x - 3^x-1 = 3^x - (3^x)/3 = (2 * 3^x)/3 = 162

=> x = ...

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by thankont » Tue Dec 19, 2006 8:38 am
You could work it out like this:
3^x-3^x-1=162 => 3^x-1*(3-1) = 162 => 3^x-1=81 =>3^x-1=3^4
so x-1=4 and x=5 and x(x-1)=20