If a, b, c and d are in continued proportion, then (a-d)/(b-c) >= x. What id x?
A. 2
B. 3
C. 1
D. 0
E. 4
OA - B
Pls explain.
A. 2
B. 3
C. 1
D. 0
E. 4
OA - B
Pls explain.
I used the following strategy
a,b,c,d are all integers increased proportionally each time thus they can be algebraically stated as;
a=x
b=x+y
c=x+2y
d=x+3y
Thus,
(a-d)/(b-c)=[x-(x+3y)]/[(x+y)-(x+2y)], simplify
(x-x-3y)/(x+y-x-2y)=-3y/-y=3
Thus, x must be at least 3 or a multiple of 3. '
Hope that helps.
Thanks,
Jared
