Krysia0101 wrote:Hi everyone,
I'm not really familiar with the use of pound sign in functions such as the following:
If #p# = ap3+ bp - 1 where a and b are constants, and #-5# = 3, what is the value of #5#?
A: 5
B: 0
C: -2
D: -3
E: -5
Thank you for any pointers!
~krysia
FOLLOW THE DIRECTIONS.
#p# = ap³ + bp - 1
implies
#-5# = a(-5)³ + b(-5) - 1 = -125a - 5b - 1.
Since #-5# = 3, we get:
-125a - 5b - 1 = 3.
-125a - 5b = 4
125a + 5b = -4.
#p# = ap³ + bp - 1
implies
#5# = a(5)³ + b(5) - 1 =
125a + 5b - 1.
Since 125a + 5b = -4,
125a + 5b - 1 = -4-1 = -5.
The correct answer is
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