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Source: — Data Sufficiency |
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by DanaJ » Sat Jan 17, 2009 10:37 am
What I would immediately notice would be that |whatever| is positive or zero, so you have:
(1) 4x - 3 >=0 so 4x>=3 so x>3/4 -----> x is positive
(2) 2x - 1>=0 so 2x >=1 so x>1/s -----> x is again positive.

Any of them will suffice.

No plugging required.....:D
Last edited by DanaJ on Sat Jan 17, 2009 10:44 am, edited 1 time in total.
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by maihuna » Sat Jan 17, 2009 10:41 am
DanaJ wrote:What I would immediately notice would be that since |whatever| is positive or zero, so you have:
(1) 4x - 3 >=0 so 4x>=3 so x>3/4 -----> x is positive
(2) 2x - 1>=0 so 2x >=1 so x>1/s -----> x is again positive.

Any of them will suffice.

No plugging required.....:D
thanks great, but i looked at it in following way:
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