-
deepesh.gupta
- Senior | Next Rank: 100 Posts
- Posts: 43
- Joined: Sun Mar 21, 2010 4:32 am
- Thanked: 1 times
BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course
Redeem
Featured Course
Target Test Prep GMAT OnDemand
Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.
- 715+ score guarantee — highest in the industry (99th percentile)
- 52 chapters · 1,500+ lessons · 4,000+ practice questions
- 400 hours of video · 1,500+ instructor-led HD smartboard lessons
- 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
- 24/7 live support + weekly Zoom office hours with GMAT instructors
- TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
- 1,200+ flashcards + AI-powered study assistant & daily calendar
- OnDemand, LiveTeach & GMAT Bootcamp formats available
- Also: GRE, SAT Math & Executive Assessment courses
- MBA Admissions Consulting now available
- 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
- 200,000+ students served
- 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★
5.0
(559 reviews)
130-pt guarantee
$0 to start
then $127/mo
Value of m
Source: Beat The GMAT — Data Sufficiency |
-
thephoenix
- Legendary Member
- Posts: 1560
- Thanked: 137 times
IMO C
m = -p + (-2)^p
1) p = even ...so p can be ...-100.....-2 , 0, 2, ....100
when p is negative
m = positive Even + positive Even fraction (as -2^p will be positive as p is even )
--> m > 1
if p = 0
m = 0 + 1 = 1 ( so m >1 doesnt hold here )
if p > 0
lets say p = 2
m = -2 + 4 = 2 and for other values (-2)^p is even bigger so m >1
Insufficient as m=1 or m>1
2) p^3 <= -1
if p = -1
m = 1 + (-2)^-1 = 1/2 thus m > 1 is not true
if p = -2
m = 2 + (-2)^-2 thus m >1 is true
c) m > 1 from 1) and 2 so its sufficient
m = -p + (-2)^p
1) p = even ...so p can be ...-100.....-2 , 0, 2, ....100
when p is negative
m = positive Even + positive Even fraction (as -2^p will be positive as p is even )
--> m > 1
if p = 0
m = 0 + 1 = 1 ( so m >1 doesnt hold here )
if p > 0
lets say p = 2
m = -2 + 4 = 2 and for other values (-2)^p is even bigger so m >1
Insufficient as m=1 or m>1
2) p^3 <= -1
if p = -1
m = 1 + (-2)^-1 = 1/2 thus m > 1 is not true
if p = -2
m = 2 + (-2)^-2 thus m >1 is true
c) m > 1 from 1) and 2 so its sufficient
