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If a=1 and b=-2...

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Source: — Problem Solving |

by Anurag@Gurome » Fri Nov 11, 2011 9:24 am
gmatpup wrote:If a = 1 and b = -2, then (2a^2 + b)(x+y) + (a+b)(x-y)=
# (2a² + b)(x + y) + (a + b)(x - y)
= (2 - 2)(x + y) + (1 - 2)(x - y)
= 0 + (-1)(x - y)
= -(x - y)
= (y - x)

The correct answer is C.
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by gmatpup » Fri Nov 11, 2011 9:40 am
Anurag@Gurome wrote:
gmatpup wrote:If a = 1 and b = -2, then (2a^2 + b)(x+y) + (a+b)(x-y)=
# (2a² + b)(x + y) + (a + b)(x - y)
= (2 - 2)(x + y) + (1 - 2)(x - y)
= 0 + (-1)(x - y)
= -(x - y)
= (y - x)

The correct answer is C.

I apologize if this sounds silly, but may I ask how you went from -(x-y) to (y-x) ? That is the difficulty I am having.

Thanks so much!!! :)
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by shikh » Mon Nov 14, 2011 2:05 am
open the brackets
-(x-y) = -x+y = y-x
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