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If xy=-15 , what is the value of xy(x-y)?
1)x+y=2
2)x^2y=45
Can we solve it with statement 1 independently with this method?
xy(x-y)= x^2y-xy^2 now if we multiply the whole with -1 it will become= -1(x^2y-xy^2), now if we take -xy as common wont the value within the bracket become (x+y), now
since we know that xy =-15 therefore - xy =15 and statement 1 gives us the value of x+y, hence we can solve the equation!
1)x+y=2
2)x^2y=45
Can we solve it with statement 1 independently with this method?
xy(x-y)= x^2y-xy^2 now if we multiply the whole with -1 it will become= -1(x^2y-xy^2), now if we take -xy as common wont the value within the bracket become (x+y), now
since we know that xy =-15 therefore - xy =15 and statement 1 gives us the value of x+y, hence we can solve the equation!













