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by sandeeptalla450 » Fri Jul 15, 2011 10:59 am
Assume each lap is 'x' miles long.
Time taken by Simon to complete 1 lap = x/60
Distance covered by Tim in this time = (x/60)*65= 13x/12

So, Tim is ahead of Simon by a distance = (13x/12) - x = x/12 ; which means that which each lap that Simon covers Tim will be ahead of him by 1/12th of a lap. So, after 2 laps Tim will be ahead of Simon by 2*(1/12)=1/6th of a lap.

So, after 12 laps, Tim will ahead of Simon by one complete lap.
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