sana.noor wrote:If p is a postive integer less than 29 and q is the remainder when 29 is divided by p, what is the value of q?
(1) p is a two-digit number.
(2) p = 3^k, where k is a positive integer.

C
however, i believe statement 2 is sufficient to answer the question. if k=1 then the remainder is 2---> 29/3 remainder is 2
if k = 2 then p is 9 and still the remiander is 2
if k = 3 then p is 27 and still the remainder is 2. the question stem says that p is less than 29 so it limits the property of p to 3, 9 or 27. in all three cases, the remiander is 2.

you are correct.

I personally find the jeff sackman's OA can't be taken for granted all the time.

If p is a postive integer less than 29 and q is the remainder when 29 is divided by p, what is the value of q?
(1) p is a two-digit number.
(2) p = 3^k, where k is a positive integer.


however, i believe statement 2 is sufficient to answer the question. if k=1 then the remainder is 2---> 29/3 remainder is 2
if k = 2 then p is 9 and still the remiander is 2
if k = 3 then p is 27 and still the remainder is 2. the question stem says that p is less than 29 so it limits the property of p to 3, 9 or 27. in all three cases, the remiander is 2.
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No just Statement 2 is not sufficient. Clearly p==q. Now if you just consider B than their can be multiple values of Q.3,9 or 27. If you include 1 than only 1 value remains(27).

lunarpower wrote:I received a message about this thread.

however, i believe statement 2 is sufficient to answer the question. if k=1 then the remainder is 2---> 29/3 remainder is 2
if k = 2 then p is 9 and still the remiander is 2
if k = 3 then p is 27 and still the remainder is 2. the question stem says that p is less than 29 so it limits the property of p to 3, 9 or 27. in all three cases, the remiander is 2.

yes.

No just Statement 2 is not sufficient. Clearly p==q. Now if you just consider B than their can be multiple values of Q.3,9 or 27. If you include 1 than only 1 value remains(27).

no. those are values of p, not values of q.

there's definitely a misunderstanding here, because you wrote "clearly p=q" (unless 2 equals signs means something else), but it's actually impossible for p and q to be the same here.
If you divide something by p, then the remainder (= q) will always be less than p, That's how remainders work.

Thanks Ron. I think sometimes i read the question too fast in order to gain time.This is one of those times.