There are six cards numbered 0, 0, 1, 2, 3, and 4. How many 3-digit even numbers are possible when picking 3 car

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[GMAT math practice question]

There are six cards numbered 0, 0, 1, 2, 3, and 4. How many 3-digit even numbers are possible when picking 3 cards?

A. 30
B. 32
C. 34
D. 36
E. 38
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Case 1: X00 (We have two zero digits.)
The number of possible cases is 4.

Case 2: X0Y / XY0 (We have one zero digit.)
X0Y: The number of possible values of y is 2 since y is an even number.
Then the number of possible values of x is 3.
Thus we have 2 * 3 = 6 cases.
XY0: The number of possible cases is 4 * 3 = 12
When we have one zero digit, we have 6 + 12 = 18 cases.

Case 3: XYZ (We don’t have any zero digits.)
The number of possible values of z is 2 since z is an even number.
Then we have 3 * 2 = 6 cases for each even integer z.
Thus we have 6 * 2 = 12 cases.

Then we have 4 + 18 + 12 = 34 cases.

Therefore, the answer is C.
Answer: C