Set A consists of integers {3, -8, Y, 19, -6} and Set B consists of integers {K, -3, 0, 16, -5, 9}. Number L repesents the median of Set A, number M repesents the median of Set B, and number Z = L ^ M. If Y is an integer greater than 21, for what value of K will Z be a divisor of 26?
A) -2
B) -1
C) 0
D) 1
E) 2
Mode, Median: Set
This topic has expert replies
-
- Master | Next Rank: 500 Posts
- Posts: 132
- Joined: Thu Dec 02, 2010 2:49 am
- Thanked: 5 times
- anshumishra
- Legendary Member
- Posts: 543
- Joined: Tue Jun 15, 2010 7:01 pm
- Thanked: 147 times
- Followed by:3 members
Set A : {-8,-6,3,19,Y}, as Y>21RadiumBall wrote:Set A consists of integers {3, -8, Y, 19, -6} and Set B consists of integers {K, -3, 0, 16, -5, 9}. Number L repesents the median of Set A, number M repesents the median of Set B, and number Z = L ^ M. If Y is an integer greater than 21, for what value of K will Z be a divisor of 26?
A) -2
B) -1
C) 0
D) 1
E) 2
So, L = 3
Set B : Either {-5,-3,0,K,9,16} Or {-5,-3,K,0,9,16}, based on the answer options range given
In both the cases , M = (0+K)/2
Z = 3^M , now only divisor of 26 which is a power of 3 could be 1
=> M = 0
So, K = 0, C
Thanks
Anshu
(Every mistake is a lesson learned )
Anshu
(Every mistake is a lesson learned )
-
- Master | Next Rank: 500 Posts
- Posts: 132
- Joined: Thu Dec 02, 2010 2:49 am
- Thanked: 5 times