IMO E

s1)dis cov in 1 min=8.8 yards=8.8/1760 =1/200 but we dnt know how much time it travel...........insuff
s2) time is given but rate is not........insuff

1+2-->t>15 hrs till 19 hrs its with in 6 miles but for t=20 hrs its exactly 6 miles and for value of t>20 hrs its more than 6 miles
hence insuff

Must be E

St1 nothing can be concluded. Only speed is given and not time
St2 Only time is given and that too more than 15 hrs, nothing can be concluded

Combine both. When train travels with a speed of 8.8 yards per minute for 15 hours it travels only 4.5 miles (Such a slow train, I will never travel with it. I can walk faster than train). Time is more than 15 hours so we can not conclude anything from this.

Thererfore, E is correct

vscid wrote:A heavily-loaded train started moving along a straight track. Was it within 6 miles of its destination when it started moving? (Note: 1 mile = 1,760 yards)

1)The train moved at a constant rate of 8.8 yards per minute.
2)The train arrived at its destination after more than 15 hours.