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Source: — Data Sufficiency |
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by ajith » Fri Feb 19, 2010 8:59 pm
gmatnmein2010 wrote:If xy ≠ 0, is x > y?

(1) 4x = 3y

(2) |y - x| = x - y
1) is not sufficient (when x is -ve x>y and when x is positive x<y)


2) |y - x| = x - y => x-y is positive x>y
Sufficient
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by thephoenix » Fri Feb 19, 2010 10:26 pm
gmatnmein2010 wrote:If xy ≠ 0, is x > y?

(1) 4x = 3y

(2) |y - x| = x - y
s1) not suff

for +ve x and +ve eqn of s1)------->x<y &
for -ve value of x and y------>x>y

s2)This means that equation |y-x|=x-y holds true when x-y>=0

bcoz ly-xl is a +ve entity

so x>=y not suff

(1)+(2) From (1) we got that x#y and from (2) x>=y , hence x>y. Sufficient.

IMO C
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by bhumika.k.shah » Sat Feb 20, 2010 12:58 am
1.)4x = 3y

If x = 3 and y = 4
then we get an answer NO for is x>y

If x=-3 and y = -4
then we get an answer YES for is x >y

hence statement 1 is sufficient.

2.)|y - x| = x - y
only when x is greater than y is this possible.

Hence B
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by harsh.champ » Sat Feb 20, 2010 6:25 am
bhumika.k.shah wrote:1.)4x = 3y

If x = 3 and y = 4
then we get an answer NO for is x>y

If x=-3 and y = -4
then we get an answer YES for is x >y

hence statement 1 is sufficient.

2.)|y - x| = x - y
only when x is greater than y is this possible.

Hence B
Hey bhumika,
I think you missed the case when (x-y) = 0
In that case also,|y - x| will be equal to x - y as |0| = 0.
Hence,x can be => y but we cannot surely say if it is not equal.
Hence,St. B would be insufficient.

I would go with C over here.
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by bhumika.k.shah » Sat Feb 20, 2010 10:17 am
whats the OA ?

if thts the case , then whats the purpose of giving xy is not equal to 0 in the question ?
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by shashank.ism » Sat Feb 20, 2010 11:46 am
gmatnmein2010 wrote:If xy ≠ 0, is x > y?

(1) 4x = 3y

(2) |y - x| = x - y

St.1 : 4x=3y --> x= 3/4 y for +ve y x<y but for -ve y x>y not sufficient
St.2: |y - x| = x - y --> y-x <=0 --> x>=y not sufficient

combined : x=y case is removed====sufficient

Ans C
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by girish3131 » Tue Mar 09, 2010 3:55 am
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Last edited by girish3131 on Tue Mar 09, 2010 4:22 am, edited 1 time in total.
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by girish3131 » Tue Mar 09, 2010 4:01 am
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