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Police Offends The Dog

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by sanju09 » Mon Mar 02, 2009 5:21 am
A police car, with their dog, who runs faster than the police car, starts chasing the fleeing offenders, when the offenders’ car, which is not running as fast as the police car, is at a straight road distance of 10 miles from the police car and the dog. As things start, the dog continues to run from the police car to the offenders’ car, and back to the police car and then to the offenders’ car, and so on till the police catches the offenders. What is the total distance in miles that the dog runs in the whole process?

(1) The police car runs 5 miles per hour faster than the offenders’ car.

(2) The dog runs at the speed of 72 miles per hour.
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by bluementor » Mon Mar 02, 2009 6:05 am
IMO E.

I'm just qualitatively answering this question. The missing info here is the relative speed of the dog to either of the cars (or the individual car speeds).

If the dog is only slightly faster than the police car, the distance travelled by the dog and the police car will not be that different.

And, if the dog is a lot more faster than the police car, the dog will be able to run a longer distance while waiting for the cops to reach the offenders.

So my guess is without knowing the speed of either of the cars, it wont be possible to work out the distance travelled by the dog. Hence E.

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by sanju09 » Mon Mar 02, 2009 6:37 am
bluementor wrote:IMO E.

I'm just qualitatively answering this question. The missing info here is the relative speed of the dog to either of the cars (or the individual car speeds).

If the dog is only slightly faster than the police car, the distance travelled by the dog and the police car will not be that different.

And, if the dog is a lot more faster than the police car, the dog will be able to run a longer distance while waiting for the cops to reach the offenders.

So my guess is without knowing the speed of either of the cars, it wont be possible to work out the distance travelled by the dog. Hence E.

:roll: [spoiler]Let's count on it![/spoiler]

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Re: Police Offends The Dog

by sureshbala » Mon Mar 02, 2009 3:18 pm
sanju09 wrote:A police car, with their dog, who runs faster than the police car, starts chasing the fleeing offenders, when the offenders’ car, which is not running as fast as the police car, is at a straight road distance of 10 miles from the police car and the dog. As things start, the dog continues to run from the police car to the offenders’ car, and back to the police car and then to the offenders’ car, and so on till the police catches the offenders. What is the total distance in miles that the dog runs in the whole process?

(1) The police car runs 5 miles per hour faster than the offenders’ car.

(2) The dog runs at the speed of 72 miles per hour.
The answer is C.

It is clear from the given question that police car has to travel 10 miles more than the offender's car in order to catch him. From the first statement, since police care travels 5 miles more in 1 hr, the police will catch up with the offender in 2 hrs.

So the dog will be traveling to and fro for these 2 hrs. But in order to give the distance traveled by the dog in 2 hrs we need its speed as well, which is given in statement 2.

Hence using both we can conclude that the dog traveled 72x2 = 144 miles
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Re: Police Offends The Dog

by bluementor » Tue Mar 03, 2009 12:51 am
sureshbala wrote:
The answer is C.

It is clear from the given question that police car has to travel 10 miles more than the offender's car in order to catch him. From the first statement, since police care travels 5 miles more in 1 hr, the police will catch up with the offender in 2 hrs.

So the dog will be traveling to and fro for these 2 hrs. But in order to give the distance traveled by the dog in 2 hrs we need its speed as well, which is given in statement 2.

Hence using both we can conclude that the dog traveled 72x2 = 144 miles
Sureshbala, you are right. I didnt realize that the distances travelled by the cars are also relative (i.e. 10 miles more), as you have clearly pointed out. In this case, we wouldnt need info on the actual speeds..Thanks.

Sanju, what's the OA?

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by sanju09 » Wed Oct 23, 2013 1:58 am
bluementor wrote:
sureshbala wrote:
The answer is C.

It is clear from the given question that police car has to travel 10 miles more than the offender's car in order to catch him. From the first statement, since police care travels 5 miles more in 1 hr, the police will catch up with the offender in 2 hrs.

So the dog will be traveling to and fro for these 2 hrs. But in order to give the distance traveled by the dog in 2 hrs we need its speed as well, which is given in statement 2.

Hence using both we can conclude that the dog traveled 72x2 = 144 miles
Sureshbala, you are right. I didnt realize that the distances travelled by the cars are also relative (i.e. 10 miles more), as you have clearly pointed out. In this case, we wouldnt need info on the actual speeds..Thanks.

Sanju, what's the OA?

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[spoiler]It's made up for C.[/spoiler]
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by lunarpower » Thu Oct 24, 2013 3:22 am
That is one fast dog.

Fastest land animal ever, in fact. (Cheetahs only run about 70 miles an hour.)

Hmm.
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by sanju09 » Thu Oct 24, 2013 4:41 am
lunarpower wrote:That is one fast dog.

Fastest land animal ever, in fact. (Cheetahs only run about 70 miles an hour.)

Hmm.
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