selango wrote:If p and n are positive integers and p > n, what is the remainder when p^2 - n^2 is divided by 15?
1) The remainder when p + n is divided by 5 is 1.
2) The remainder when p - n is divided by 3 is 1.
OA E
Can anyone explain in detail?
Here's another approach. We can rewrite the question as follows:
What is the remainder when (p+n)(p-n) is divided by 15?
The two statements give us information about p+n and p-n. Let's make a list of the possible values that p+n and p-n could assume.
Statement 1:
If when p + n is divided by 5 the remainder is 1, then p + n must be a (multiple of 5) + 1. Why? So that when we divide p + n by 5, we'll have 1 left over.
p + n = 1, 6, 11, 16, 21, 26, 31... (Remember that 0 is a multiple of every number; that's why 1 is included in our list.)
But statement 1 tells us nothing about p - n.
INSUFFICIENT.
Statement 2:
If when p - n is divided by 3 the remainder is 1, then p - n must be a (multiple of 3) + 1. Why? So that when we divide p - n by 3, we'll have 1 left over.
p - n = 1, 4, 7, 10, 13, 16...(Remember that 0 is a multiple of every number; that's why 1 is included in our list.)
But statement 2 tells us nothing about p + n.
INSUFFICIENT.
Statements 1 and 2 together:
p + n = 1, 6, 11, 16, 21, 26, 31...
p - n = 1, 4, 7, 10, 13, 16...
If p = 11 and n = 10, then p>n and p + n = 21 and p - n = 1, both of which are included in our lists above.
In this case, (p + n)(p - n) = 21 * 1 = 21. What's the remainder when 21 is divided by 15? 21/15 = 1 R6. The remainder is 6.
If p = 16 and n = 15, then p>n and p + n = 31 and p - n = 1, both of which are included in our lists above.
In this case, (p + n)(p - n) = 31 * 1 = 31. What's the remainder when 31 is divided by 15? 31/15 = 1 R16. The remainder is 16.
Since the remainder can be different values,
INSUFFICIENT.
The correct answer is E.
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